I'm writing a command line utility in Python which, since it is production code, ought to be able to shut down cleanly without dumping a bunch of stuff (error codes, stack traces, etc.) to the screen. This means I need to catch keyboard interrupts.
I've tried using both a try catch block like:
if __name__ == '__main__': try: main() except KeyboardInterrupt: print 'Interrupted' sys.exit(0) and catching the signal itself (as in this post):
import signal import sys def sigint_handler(signal, frame): print 'Interrupted' sys.exit(0) signal.signal(signal.SIGINT, sigint_handler) Both methods seem to work quite well during normal operation. However, if the interrupt comes during cleanup code at the end of the application, Python seems to always print something to the screen. Catching the interrupt gives
^CInterrupted Exception KeyboardInterrupt in <bound method MyClass.__del__ of <path.to.MyClass object at 0x802852b90>> ignored whereas handling the signal gives either
^CInterrupted Exception SystemExit: 0 in <Finalize object, dead> ignored or
^CInterrupted Exception SystemExit: 0 in <bound method MyClass.__del__ of <path.to.MyClass object at 0x802854a90>> ignored Not only are these errors ugly, they're not very helpful (especially to an end user with no source code)!
The cleanup code for this application is fairly big, so there's a decent chance that this issue will be hit by real users. Is there any way to catch or block this output, or is it just something I'll have to deal with?
62 Answers
Checkout this thread, it has some useful information about exiting and tracebacks.
If you are more interested in just killing the program, try something like this (this will take the legs out from under the cleanup code as well):
if __name__ == '__main__': try: main() except KeyboardInterrupt: print('Interrupted') try: sys.exit(0) except SystemExit: os._exit(0) You could ignore SIGINTs after shutdown starts by calling signal.signal(signal.SIGINT, signal.SIG_IGN) before you start your cleanup code.
