CURL error "URL using bad/illegal format or missing URL" when trying to pass variable as a part of URL

When I'm trying to execute script below and getting error: "curl: (3) URL using bad/illegal format or missing URL"

#!/bin/bash stage="develop" branch="branch_name" getDefinition=$(curl -u :password -X GET "") for def in $(echo "$getDefinition" | jq '.value[] | select (.path=="\\Some_path\\'$stage'") | .id'); do getBuildInfo=$(curl -u :password -X GET "") # echo $def body=$(echo "${getBuildInfo}" | jq '.repository.defaultBranch = "refs/heads/release/'"${branch}"'"' | jq '.options[].inputs.branchFilters = "[\"+refs/heads/release/'"${branch}"'\"]"' | jq '.triggers[].branchFilters[] = "+refs/heads/release/'"${branch}"'"') echo ${body} > data.json done 

It happens when I'm trying to pass variable ${def} into a line:

curl -u :password -X GET "" 

But when I declare an array, curl works as expected. Example:

declare -a def def=(1 2 3 4) curl -u :password -X GET "" 

Could you please suggest how can I pass variable into URL properly?

1 Answer

Do you need to call curl for 4 times? If so.

for def in 1 2 3 4; do curl -u :password -X GET ""; done