I am taking a class in C++ and I noticed there are only a few math operators to use. I also noticed that C++ does not come with an exponential operator within its math library.
Why must one always write a function for this? Is there a reason for the makers of C++ to omit this operator?
14 Answers
You don't write a function for this (unless you're insane, of course). There's a perfectly good pow function defined in the <cmath> header.
1Aside: if you try to use
^as a power operator, as some people are wont to do, you'll be in for a nasty surprise. It's the exclusive-or (XOR) operator (see here).
According to Bjarne Stroustrup in his book The design and evolution of C++. They decided to avoid exponential operator because :
- An operator provides notational convenience, but does not provide any new functionality. Members of the working group, representing heavy users of scientific/engineering computation, indicated that the operator syntax provides minor syntactic convenience.
- Every user of C++ must learn this new feature
- Users have stressed the importance of susbtituting their own specialized exponentiation functions for the system default, which would not be possible with an intrinsic operator
- The proposal is not sufficiently well motivated. In particular, by looking at one 30000 line Fortran program one cannot conclude that the operator would be widely used in C++
- The proposal requires adding a new operator and adding another precedence level thus increasing the complexity of the language
Most C operations readily intended to mapped to a single processor instruction when C was invented. At the time, exponentiation was not a machine instruction, thus the library routine.
Python has the ** operator for exponentiation. In C++ you can actually define an operator like that with some trickery. By combining the unary * operator with the binary * operator, like this:
#include <cmath> #include <iostream> struct Num { double value; Num(double value) : value(value) { } typedef Num* HalfStar; HalfStar operator*() const { return HalfStar(this); } Num operator*(const HalfStar& rhs) const { return Num(std::pow(value, rhs->value)); } Num operator*(const Num& rhs) const { return Num(value * rhs.value); } friend std::ostream& operator<<(std::ostream& os, const Num& n) { return os << n.value; } }; int main(int argc, char**argv) { Num a = 10; Num b = 9; std::cout << "a*b = " << (a*b) << "\n"; std::cout << "a**b = " << (a**b) << "\n"; return 0; } This will not work with non-class types though, so you can not do: x**2.
See here for a live example.
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