I used grep that outputs a list like this
/player/ABc12 /player/ABC321 /player/EGF987 /player/egf751 However I want to only give the name of the players such ABC321, EFG987, etc...
4 Answers
Start using grep :
$ grep -oP "/player/\K.*" FILE ABc12 ABC321 EGF987 egf751 Or shorter :
$ grep -oP "[^/]/\K.*" FILE ABc12 ABC321 EGF987 egf751 Or without -P (pcre) option :
$ grep -o '[^/]\+$' FILE ABc12 ABC321 EGF987 egf751 Or with pure bash :
$ IFS=/ oIFS=$IFS $ while read a b c; do echo $c; done < FILE ABc12 ABC321 EGF987 egf751 $ IFS=$oIFS @sputnick has the right idea with grep, and something like that would actually be my preferred solution. I personally immediately thought of a positive lookbehind:
grep -oP '(?<=/player/)\w+' file But the \K works perfectly fine as well.
An alternative (somewhat shorter) solution is with sed:
sed 's:.*/::' file Stop using grep.
$ awk -F/ '$2 == "player" { print $3 }' input.txt ABc12 ABC321 EGF987 egf751 One way using GNU grep and a positive lookbehind:
grep -oP '(?<=^/player/).*' file.txt Results:
ABc12 ABC321 EGF987 egf751 
