We've got a PHP application and want to count all the lines of code under a specific directory and its subdirectories.
We don't need to ignore comments, as we're just trying to get a rough idea.
wc -l *.php That command works great for a given directory, but it ignores subdirectories. I was thinking the following comment might work, but it is returning 74, which is definitely not the case...
find . -name '*.php' | wc -l What's the correct syntax to feed in all the files from a directory resursively?
48 Answers
Try:
find . -name '*.php' | xargs wc -l or (when file names include special characters such as spaces)
find . -name '*.php' | sed 's/.*/"&"/' | xargs wc -l The SLOCCount tool may help as well.
It will give an accurate source lines of code count for whatever hierarchy you point it at, as well as some additional stats.
Sorted output:
find . -name '*.php' | xargs wc -l | sort -nr
For another one-liner:
( find ./ -name '*.php' -print0 | xargs -0 cat ) | wc -l It works on names with spaces and only outputs one number.
19You can use the cloc utility which is built for this exact purpose. It reports each the amount of lines in each language, together with how many of them are comments, etc. CLOC is available on Linux, Mac and Windows.
Usage and output example:
$ cloc --exclude-lang=DTD,Lua,make,Python . 2570 text files. 2200 unique files. 8654 files ignored. v 1.53 T=8.0 s (202.4 files/s, 99198.6 lines/s) ------------------------------------------------------------------------------- Language files blank comment code ------------------------------------------------------------------------------- JavaScript 1506 77848 212000 366495 CSS 56 9671 20147 87695 HTML 51 1409 151 7480 XML 6 3088 1383 6222 ------------------------------------------------------------------------------- SUM: 1619 92016 233681 467892 ------------------------------------------------------------------------------- If using a decently recent version of Bash (or ZSH), it's much simpler:
wc -l **/*.php In the Bash shell this requires the globstar option to be set, otherwise the ** glob-operator is not recursive. To enable this setting, issue
shopt -s globstar To make this permanent, add it to one of the initialization files (~/.bashrc, ~/.bash_profile etc.).
On Unix-like systems, there is a tool called cloc which provides code statistics.
I ran in on a random directory in our code base it says:
59 text files. 56 unique files. 5 files ignored. v 1.53 T=0.5 s (108.0 files/s, 50180.0 lines/s) ------------------------------------------------------------------------------- Language files blank comment code ------------------------------------------------------------------------------- C 36 3060 1431 16359 C/C++ Header 16 689 393 3032 make 1 17 9 54 Teamcenter def 1 10 0 36 ------------------------------------------------------------------------------- SUM: 54 3776 1833 19481 ------------------------------------------------------------------------------- You didn't specify how many files are there or what is the desired output.
This may be what you are looking for:
find . -name '*.php' | xargs wc -l Yet another variation :)
$ find . -name '*.php' | xargs cat | wc -l This will give the total sum, instead of file-by-file.
Add . after find to make it work.
Use find's -exec and awk. Here we go:
find . -type f -exec wc -l {} \; | awk '{ SUM += $0} END { print SUM }' This snippet finds for all files (-type f). To find by file extension, use -name:
find . -name '*.py' -exec wc -l '{}' \; | awk '{ SUM += $0; } END { print SUM; }' More common and simple as for me, suppose you need to count files of different name extensions (say, also natives):
wc $(find . -type f | egrep "\.(h|c|cpp|php|cc)" ) POSIX
Unlike most other answers here, these work on any POSIX system, for any number of files, and with any file names (except where noted).
Lines in each file:
find . -name '*.php' -type f -exec wc -l {} \; # faster, but includes total at end if there are multiple files find . -name '*.php' -type f -exec wc -l {} + Lines in each file, sorted by file path
find . -name '*.php' -type f | sort | xargs -L1 wc -l # for files with spaces or newlines, use the non-standard sort -z find . -name '*.php' -type f -print0 | sort -z | xargs -0 -L1 wc -l Lines in each file, sorted by number of lines, descending
find . -name '*.php' -type f -exec wc -l {} \; | sort -nr # faster, but includes total at end if there are multiple files find . -name '*.php' -type f -exec wc -l {} + | sort -nr Total lines in all files
find . -name '*.php' -type f -exec cat {} + | wc -l There is a little tool called sloccount to count the lines of code in a directory.
It should be noted that it does more than you want as it ignores empty lines/comments, groups the results per programming language and calculates some statistics.
2The tool Tokei displays statistics about code in a directory. Tokei will show the number of files, total lines within those files and code, comments, and blanks grouped by language. Tokei is also available on Mac, Linux, and Windows.
An example of the output of Tokei is as follows:
$ tokei ------------------------------------------------------------------------------- Language Files Lines Code Comments Blanks ------------------------------------------------------------------------------- CSS 2 12 12 0 0 JavaScript 1 435 404 0 31 JSON 3 178 178 0 0 Markdown 1 9 9 0 0 Rust 10 408 259 84 65 TOML 3 69 41 17 11 YAML 1 30 25 0 5 ------------------------------------------------------------------------------- Total 21 1141 928 101 112 ------------------------------------------------------------------------------- Tokei can be installed by following the instructions on the README file in the repository.
1You want a simple for loop:
total_count=0 for file in $(find . -name *.php -print) do count=$(wc -l $file) let total_count+=count done echo "$total_count" For sources only:
wc `find` To filter, just use grep:
wc `find | grep .php$` A straightforward one that will be fast, will use all the search/filtering power of find, not fail when there are too many files (number arguments overflow), work fine with files with funny symbols in their name, without using xargs, and will not launch a uselessly high number of external commands (thanks to + for find's -exec). Here you go:
find . -name '*.php' -type f -exec cat -- {} + | wc -l I know the question is tagged as bash, but it seems that the problem you're trying to solve is also PHP related.
Sebastian Bergmann wrote a tool called PHPLOC that does what you want and on top of that provides you with an overview of a project's complexity. This is an example of its report:
Size Lines of Code (LOC) 29047 Comment Lines of Code (CLOC) 14022 (48.27%) Non-Comment Lines of Code (NCLOC) 15025 (51.73%) Logical Lines of Code (LLOC) 3484 (11.99%) Classes 3314 (95.12%) Average Class Length 29 Average Method Length 4 Functions 153 (4.39%) Average Function Length 1 Not in classes or functions 17 (0.49%) Complexity Cyclomatic Complexity / LLOC 0.51 Cyclomatic Complexity / Number of Methods 3.37 As you can see, the information provided is a lot more useful from the perspective of a developer, because it can roughly tell you how complex a project is before you start working with it.
None of the answers so far gets at the problem of filenames with spaces.
Additionally, all that use xargs are subject to fail if the total length of paths in the tree exceeds the shell environment size limit (defaults to a few megabytes in Linux).
Here is one that fixes these problems in a pretty direct manner. The subshell takes care of files with spaces. The awk totals the stream of individual file wc outputs, so it ought never to run out of space. It also restricts the exec to files only (skipping directories):
find . -type f -name '*.php' -exec bash -c 'wc -l "$0"' {} \; | awk '{s+=$1} END {print s}' If you want to keep it simple, cut out the middleman and just call wc with all the filenames:
wc -l `find . -name "*.php"` Or in the modern syntax:
wc -l $(find . -name "*.php") This works as long as there are no spaces in any of the directory names or filenames. And as long as you don't have tens of thousands of files (modern shells support really long command lines). Your project has 74 files, so you've got plenty of room to grow.
1WC -L ? better use GREP -C ^
wc -l? Wrong!
The wc command counts new lines codes, not lines! When the last line in the file does not end with new line code, this will not be counted!
If you still want count lines, use grep -c ^. Full example:
# This example prints line count for all found files total=0 find /path -type f -name "*.php" | while read FILE; do # You see, use 'grep' instead of 'wc'! for properly counting count=$(grep -c ^ < "$FILE") echo "$FILE has $count lines" let total=total+count #in bash, you can convert this for another shell done echo TOTAL LINES COUNTED: $total Finally, watch out for the wc -l trap (counts enters, not lines!!!)
Giving out the longest files first (ie. maybe these long files need some refactoring love?), and excluding some vendor directories:
find . -name '*.php' | xargs wc -l | sort -nr | egrep -v "libs|tmp|tests|vendor" | less For Windows, an easy-and-quick tool is LocMetrics.
3You can use a utility called codel (link). It's a simple Python module to count lines with colorful formatting.
Installation
pip install codel Usage
To count lines of C++ files (with .cpp and .h extensions), use:
codel count -e .cpp .h You can also ignore some files/folder with the .gitignore format:
codel count -e .py -i tests/** It will ignore all the files in the tests/ folder.
The output looks like:
You also can shorten the output with the -s flag. It will hide the information of each file and show only information about each extension. The example is below:
If you want your results sorted by number of lines, you can just add | sort or | sort -r (-r for descending order) to the first answer, like so:
find . -name '*.php' | xargs wc -l | sort -r Very simply:
find /path -type f -name "*.php" | while read FILE do count=$(wc -l < $FILE) echo "$FILE has $count lines" done Something different:
wc -l `tree -if --noreport | grep -e'\.php$'` This works out fine, but you need to have at least one *.php file in the current folder or one of its subfolders, or else wc stalls.
It’s very easy with Z shell (zsh) globs:
wc -l ./**/*.php If you are using Bash, you just need to upgrade. There is absolutely no reason to use Bash.
On OS X at least, the find+xarg+wc commands listed in some of the other answers prints "total" several times on large listings, and there is no complete total given. I was able to get a single total for .c files using the following command:
find . -name '*.c' -print0 |xargs -0 wc -l|grep -v total|awk '{ sum += $1; } END { print "SUM: " sum; }'
If the files are too many, better to just look for the total line count.
find . -name '*.php' | xargs wc -l | grep -i ' total' | awk '{print $1}' If you need just the total number of lines in, let's say, your PHP files, you can use very simple one line command even under Windows if you have GnuWin32 installed. Like this:
cat `/gnuwin32/bin/find.exe . -name *.php` | wc -l You need to specify where exactly is the find.exe otherwise the Windows provided FIND.EXE (from the old DOS-like commands) will be executed, since it is probably before the GnuWin32 in the environment PATH and has different parameters and results.
Please note that in the command above you should use back-quotes, not single quotes.
1While I like the scripts, I prefer this one as it also shows a per-file summary as long as a total:
wc -l `find . -name "*.php"` 
