How can I truncate a double to only two decimal places in Java?

For example I have the variable 3.545555555, which I would want to truncate to just 3.54.

17 Answers

If you want that for display purposes, use java.text.DecimalFormat:

 new DecimalFormat("#.##").format(dblVar); 

If you need it for calculations, use java.lang.Math:

 Math.floor(value * 100) / 100; 

DecimalFormat df = new DecimalFormat(fmt); df.setRoundingMode(RoundingMode.DOWN); s = df.format(d); 

Check available RoundingMode and DecimalFormat.

None of the other answers worked for both positive and negative values ( I mean for the calculation and just to do "truncate" without Rounding). and without converting to string.

From the How to round a number to n decimal places in Java link

private static BigDecimal truncateDecimal(double x,int numberofDecimals) { if ( x > 0) { return new BigDecimal(String.valueOf(x)).setScale(numberofDecimals, BigDecimal.ROUND_FLOOR); } else { return new BigDecimal(String.valueOf(x)).setScale(numberofDecimals, BigDecimal.ROUND_CEILING); } } 

This method worked fine for me .

System.out.println(truncateDecimal(0, 2)); System.out.println(truncateDecimal(9.62, 2)); System.out.println(truncateDecimal(9.621, 2)); System.out.println(truncateDecimal(9.629, 2)); System.out.println(truncateDecimal(9.625, 2)); System.out.println(truncateDecimal(9.999, 2)); System.out.println(truncateDecimal(-9.999, 2)); System.out.println(truncateDecimal(-9.0, 2)); 

Results :

0.00 9.62 9.62 9.62 9.62 9.99 -9.99 -9.00 

Note first that a double is a binary fraction and does not really have decimal places.

If you need decimal places, use a BigDecimal, which has a setScale() method for truncation, or use DecimalFormat to get a String.

If, for whatever reason, you don't want to use a BigDecimal you can cast your double to an int to truncate it.

If you want to truncate to the Ones place:

• simply cast to int

To the Tenths place:

• multiply by ten
• cast to int
• cast back to double
• and divide by ten.

Hundreths place

• multiply and divide by 100 etc.

Example:

static double truncateTo( double unroundedNumber, int decimalPlaces ){ int truncatedNumberInt = (int)( unroundedNumber * Math.pow( 10, decimalPlaces ) ); double truncatedNumber = (double)( truncatedNumberInt / Math.pow( 10, decimalPlaces ) ); return truncatedNumber; } 

In this example, decimalPlaces would be the number of places PAST the ones place you wish to go, so 1 would round to the tenths place, 2 to the hundredths, and so on (0 rounds to the ones place, and negative one to the tens, etc.)

Formating as a string and converting back to double i think will give you the result you want.

The double value will not be round(), floor() or ceil().

A quick fix for it could be:

 String sValue = (String) String.format("%.2f", oldValue); Double newValue = Double.parseDouble(sValue); 

You can use the sValue for display purposes or the newValue for calculation.

You can use NumberFormat Class object to accomplish the task.

// Creating number format object to set 2 places after decimal point NumberFormat nf = NumberFormat.getInstance(); nf.setMaximumFractionDigits(2); nf.setGroupingUsed(false); System.out.println(nf.format(precision));// Assuming precision is a double type variable 

3.545555555 to get 3.54. Try Following for this:

 DecimalFormat df = new DecimalFormat("#.##"); df.setRoundingMode(RoundingMode.FLOOR); double result = new Double(df.format(3.545555555); 

This will give= 3.54!

Maybe Math.floor(value * 100) / 100? Beware that the values like 3.54 may be not exactly represented with a double.

Here is the method I use:

double a=3.545555555; // just assigning your decimal to a variable a=a*100; // this sets a to 354.555555 a=Math.floor(a); // this sets a to 354 a=a/100; // this sets a to 3.54 and thus removing all your 5's 

This can also be done:

a=Math.floor(a*100) / 100; 

Maybe following :

double roundTwoDecimals(double d) { DecimalFormat twoDForm = new DecimalFormat("#.##"); return Double.valueOf(twoDForm.format(d)); } 

A quick check is to use the Math.floor method. I created a method to check a double for two or less decimal places below:

public boolean checkTwoDecimalPlaces(double valueToCheck) { // Get two decimal value of input valueToCheck double twoDecimalValue = Math.floor(valueToCheck * 100) / 100; // Return true if the twoDecimalValue is the same as valueToCheck else return false return twoDecimalValue == valueToCheck; } 

 double value = 3.4555; String value1 = String.format("% .3f", value) ; String value2 = value1.substring(0, value1.length() - 1); System.out.println(value2); double doublevalue= Double.valueOf(value2); System.out.println(doublevalue); 

I used Math.floor() method and basic moving of decimal places by (100 = 2).

//3.545555555 to 3.54 by floor method double x = 3.545555555; double y = Math.floor(x * 100); //354 double z = y / 100; //3.54 

double firstValue = -3.1756d;

double value1 = (((int)(Math.pow(10,3)*firstValue))/Math.pow(10,3));

I have a slightly modified version of Mani's.

private static BigDecimal truncateDecimal(final double x, final int numberofDecimals) { return new BigDecimal(String.valueOf(x)).setScale(numberofDecimals, BigDecimal.ROUND_DOWN); } public static void main(String[] args) { System.out.println(truncateDecimal(0, 2)); System.out.println(truncateDecimal(9.62, 2)); System.out.println(truncateDecimal(9.621, 2)); System.out.println(truncateDecimal(9.629, 2)); System.out.println(truncateDecimal(9.625, 2)); System.out.println(truncateDecimal(9.999, 2)); System.out.println(truncateDecimal(3.545555555, 2)); System.out.println(truncateDecimal(9.0, 2)); System.out.println(truncateDecimal(-9.62, 2)); System.out.println(truncateDecimal(-9.621, 2)); System.out.println(truncateDecimal(-9.629, 2)); System.out.println(truncateDecimal(-9.625, 2)); System.out.println(truncateDecimal(-9.999, 2)); System.out.println(truncateDecimal(-9.0, 2)); System.out.println(truncateDecimal(-3.545555555, 2)); } 

Output:

0.00 9.62 9.62 9.62 9.62 9.99 9.00 3.54 -9.62 -9.62 -9.62 -9.62 -9.99 -9.00 -3.54 

This worked for me:

double input = 104.8695412 //For example long roundedInt = Math.round(input * 100); double result = (double) roundedInt/100; //result == 104.87 

I personally like this version because it actually performs the rounding numerically, rather than by converting it to a String (or similar) and then formatting it.