Trying to assert that two dictionaries that have nested contents are equal to each other (order doesn't matter) with pytest. What's the pythonic way to do this?
16 Answers
Don't spend your time writing this logic yourself. Just use the functions provided by the default testing library unittest
from unittest import TestCase TestCase().assertDictEqual(expected_dict, actual_dict) pytest's magic is clever enough. By writing
assert {'a': {'b': 2, 'c': {'d': 4} } } == {'a': {'b': 2, 'c': {'d': 4} } } you will have a nested test on equality.
0I guess a simple assert equality test should be okay:
>>> d1 = {n: chr(n+65) for n in range(10)} >>> d2 = {n: chr(n+65) for n in range(10)} >>> d1 == d2 True >>> l1 = [1, 2, 3] >>> l2 = [1, 2, 3] >>> d2[10] = l2 >>> d1[10] = l1 >>> d1 == d2 True >>> class Example: stub_prop = None >>> e1 = Example() >>> e2 = Example() >>> e2.stub_prop = 10 >>> e1.stub_prop = 'a' >>> d1[11] = e1 >>> d2[11] = e2 >>> d1 == d2 False General purpose way is to:
import json # Make sure you sort any lists in the dictionary before dumping to a string dictA_str = json.dumps(dictA, sort_keys=True) dictB_str = json.dumps(dictB, sort_keys=True) assert dictA_str == dictB_str 1assert all(v == actual_dict[k] for k,v expected_dict.items()) and len(expected_dict) == len(actual_dict) 2your question is not very specific but with what i can understand, you are either trying to check if the length are the same
a = [1,5,3,6,3,2,4] b = [5,3,2,1,3,5,3] if (len(a) == len(b)): print True else: print false or checking if the list values are the same
import collections compare = lambda x, y: collections.Counter(x) == collections.Counter(y) compare([1,2,3], [1,2,3,3]) print compare #answer would be false compare([1,2,3], [1,2,3]) print compare #answer would be true but for dictionaries you could also use
x = dict(a=1, b=2) y = dict(a=2, b=2) if(x == y): print True else: print False