I want to output my key value pairs from a python dictionary as such:
key1 \t value1 key2 \t value2 I thought I could maybe do it like this:
for i in d: print d.keys(i), d.values(i) but obviously that's not how it goes as the keys() and values() don't take an argument.
12 Answers
Python 2 and Python 3
i is the key, so you would just need to use it:
for i in d: print i, d[i] Python 3
d.items() returns the iterator; to get a list, you need to pass the iterator to list() yourself.
for k, v in d.items(): print(k, v) Python 2
You can get an iterator that contains both keys and values. d.items() returns a list of (key, value) tuples, while d.iteritems() returns an iterator that provides the same:
for k, v in d.iteritems(): print k, v A little intro to dictionary
d={'a':'apple','b':'ball'} d.keys() # displays all keys in list ['a','b'] d.values() # displays your values in list ['apple','ball'] d.items() # displays your pair tuple of key and value [('a','apple'),('b','ball') Print keys,values method one
for x in d.keys(): print(x +" => " + d[x]) Another method
for key,value in d.items(): print(key + " => " + value) You can get keys using iter
>>> list(iter(d)) ['a', 'b'] You can get value of key of dictionary using get(key, [value]):
d.get('a') 'apple' If key is not present in dictionary,when default value given, will return value.
d.get('c', 'Cat') 'Cat' Or, for Python 3:
for k,v in dict.items(): print(k, v) The dictionary:
d={'key1':'value1','key2':'value2','key3':'value3'} Another one line solution:
print(*d.items(), sep='\n') Output:
('key1', 'value1') ('key2', 'value2') ('key3', 'value3') (but, since no one has suggested something like this before, I suspect it is not good practice)
3for key, value in d.iteritems(): print key, '\t', value You can access your keys and/or values by calling items() on your dictionary.
for key, value in d.iteritems(): print(key, value) If you want to sort the output by dict key you can use the collection package.
import collections for k, v in collections.OrderedDict(sorted(d.items())).items(): print(k, v) It works on python 3
>>> d={'a':1,'b':2,'c':3} >>> for kv in d.items(): ... print kv[0],'\t',kv[1] ... a 1 c 3 b 2 In addition to ways already mentioned.. can use 'viewitems', 'viewkeys', 'viewvalues'
>>> d = {320: 1, 321: 0, 322: 3} >>> list(d.viewitems()) [(320, 1), (321, 0), (322, 3)] >>> list(d.viewkeys()) [320, 321, 322] >>> list(d.viewvalues()) [1, 0, 3] Or
>>> list(d.iteritems()) [(320, 1), (321, 0), (322, 3)] >>> list(d.iterkeys()) [320, 321, 322] >>> list(d.itervalues()) [1, 0, 3] or using itemgetter
>>> from operator import itemgetter >>> map(itemgetter(0), dd.items()) #### for keys ['323', '332'] >>> map(itemgetter(1), dd.items()) #### for values ['3323', 232] A simple dictionary:
x = {'X':"yes", 'Y':"no", 'Z':"ok"} To print a specific (key, value) pair in Python 3 (pair at index 1 in this example):
for e in range(len(x)): print(([x for x in x.keys()][e], [x for x in x.values()][e])) Output:
('X', 'yes') ('Y', 'no') ('Z', 'ok') Here is a one liner solution to print all pairs in a tuple:
print(tuple(([x for x in x.keys()][i], [x for x in x.values()][i]) for i in range(len(x)))) Output:
(('X', 'yes'), ('Y', 'no'), ('Z', 'ok')) To Print key-value pair, for example:
players = { 'lebron': 'lakers', 'giannis': 'milwakee bucks', 'durant': 'brooklyn nets', 'kawhi': 'clippers', } for player,club in players.items():
print(f"\n{player.title()} is the leader of {club}") The above code, key-value pair:
'lebron': 'lakers', - Lebron is key and lakers is value for loop - specify key, value in dictionary.item():
Now Print (Player Name is the leader of club).
the Output is:
#Lebron is the leader of lakers #Giannis is the leader of milwakee bucks #Durant is the leader of brooklyn nets #Kawhi is the leader of clippers If you're looking for pretty-printing a dictionary, check out Rich:
from rich import print prices = { "banana": 4, "apple": 2, "orange": 1.5, "pear": 3, "strawberry": 1, "blueberry": 0.5, "mango": 4.5 } print(prices) 
