Does anyone know how to create a BitmapImage from an Image? Here is the code that I'm working with:
MemoryStream memStream = new MemoryStream(bytes); Image img = Image.FromStream(memStream); Now I have access to this image in memory. The thing is I need to convert this to type BitmapImage in order to use it in my solution.
NOTE: I need to convert it to type BitmapImage not type Bitmap. I haven't been able to figure it out because type BitmapImage takes in a Uri for it's constructor.
4 Answers
Bitmap img = (Bitmap) Image.FromStream(memStream); BitmapImage bmImg = new BitmapImage(); using (MemoryStream memStream2 = new MemoryStream()) { img.Save(memStream2, System.Drawing.Imaging.ImageFormat.Png); memStream2.Position = 0; bmImg.BeginInit(); bmImg.CacheOption = BitmapCacheOption.OnLoad; bmImg.UriSource = null; bmImg.StreamSource = memStream2; bmImg.EndInit(); } From this post
public BitmapImage ImageFromBuffer(Byte[] bytes) { MemoryStream stream = new MemoryStream(bytes); BitmapImage image = new BitmapImage(); image.BeginInit(); image.StreamSource = stream; image.EndInit(); return image; } Are you sure you need BitmapImage, not BitmapSource? BitmapImage is a subclass of BitmapSource specifically for making a source in XAML (from a URI). There are many other BitmapSource choices -- one of the other choices might be better.
For example, WriteableBitmap
You can make one of the size you want, and then copy pixels over to it.
Saving in a memory stream doesn't work for images created in memory. So I improved the already existing answers as follows:
ImageConverter converter = new ImageConverter(); byte[] buffer = (byte[])converter.ConvertTo(image, typeof(byte[])); MemoryStream loadStream = new MemoryStream(buffer); BitmapImage returnValue = new(); returnValue.BeginInit(); returnValue.StreamSource = loadStream; returnValue.EndInit(); return returnValue; 
