I am able to get date and time using:
DateTime now = DateTime.Now; How can I get the current date and time separately in the DateTime format itself?
I am not using the DateTime picker dialog box in ASP.NET (C#).
14 Answers
Well, you can get just today's date as a DateTime using the Today property:
DateTime today = DateTime.Today; or more generally, you can use the Date property. For example, if you wanted the UTC date you could use:
DateTime dateTime = DateTime.UtcNow.Date; It's not very clear whether that's what you need or not though... if you're just looking to print the date, you can use:
Console.WriteLine(dateTime.ToString("d")); or use an explicit format:
Console.WriteLine(dateTime.ToString("dd/MM/yyyy")); See more about standard and custom date/time format strings. Depending on your situation you may also want to specify the culture.
If you want a more expressive date/time API which allows you to talk about dates separately from times, you might want to look at the Noda Time project which I started. It's not ready for production just yet, but we'd love to hear what you'd like to do with it...
See, here you can get only date by passing a format string. You can get a different date format as per your requirement as given below for current date:
DateTime.Now.ToString("M/d/yyyy"); Result : "9/1/2015"
DateTime.Now.ToString("M-d-yyyy"); Result : "9-1-2015"
DateTime.Now.ToString("yyyy-MM-dd"); Result : "2015-09-01"
DateTime.Now.ToString("yyyy-MM-dd hh:mm:ss"); Result : "2015-09-01 09:20:10"
For more details take a look at MSDN reference for Custom Date and Time Format Strings
0Use DateTime.Today property. It will return date component of DateTime.Now. It is equivalent of DateTime.Now.Date.
Starting from .NET 6 you might also consider using DateOnly and TimeOnly
Current Time :
DateTime.Now.ToString("HH:mm:ss"); Current Date :
DateTime.Today.ToString("dd-MM-yyyy"); You can use following code to get the date and time separately.
DateTime now = DateTime.Now; string date = now.GetDateTimeFormats('d')[0]; string time = now.GetDateTimeFormats('t')[0]; You can also, check the MSDN for more information.
There is no built-in date-only type in .NET.
The convention is to use a DateTime with the time portion set to midnight.
The static DateTime.Today property will give you today's date.
Use
txtdate.Text = DateTime.Today.ToString("dd-MM-yyyy"); I think you need separately date parts like (day, Month, Year)
DateTime today = DateTime.Today;
Will not work for your case. You can get date separately so you don't need variable today to be as a DateTimeType, so lets just give today variable int Type because the day is only int. So today is 10 March 2020 then the result of
int today = DateTime.Today.Day;
int month = DateTime.Today.Month;
int year = DateTime.Today.Year;
MessageBox.Show(today.ToString()+ " - this is day. "+month.ToString()+ " - this is month. " + year.ToString() + " - this is year");
would be "10 - this is day. 3 - this is month. 2020 - this is year"
In .Net6, you can use the new DateOnly Type :
DateOnly.FromDateTime(DateTime.Today) You can use DateTime.Now.ToShortDateString() like so:
var test = $"<b>Date of this report:</b> {DateTime.Now.ToShortDateString()}"; As of .Net 6 you can use:
var dateOnly = DateOnly.FromDateTime(DateTime.Now); string now = Convert.ToString(DateTime.Now.ToShortDateString()); Console.WriteLine(now); Console.ReadLine(); for month
DateTime.Now.ToString("MM"); for day
DateTime.Now.ToString("dd"); for year
DateTime.Now.ToString("yyyy"); DateTime.Now.ToString("dd/MM/yyyy"); 0