How to open a URL in python

import urllib fun open(): return urllib.urlopen(') 

But when example.com opens it does not render CSS or JavaScript. How can I open the webpage in a web browser?

@error(404) def error404(error): return webbrowser.open(') 

I am using bottle. Giving me the error:

TypeError("'bool' object is not iterable",) 

7 Answers

with the webbrowser module

import webbrowser webbrowser.open(') # Go to example.com 

import webbrowser webbrowser.open(url, new=0, autoraise=True) 

Display url using the default browser. If new is 0, the url is opened in the same browser window if possible. If new is 1, a new browser window is opened if possible. If new is 2, a new browser page (“tab”) is opened if possible. If autoraise is True, the window is raised

webbrowser.open_new(url) 

Open url in a new window of the default browser

webbrowser.open_new_tab(url) 

Open url in a new page (“tab”) of the default browser

On Windows

import os os.system("start \"\" ") 

On macOS

import os os.system("open \"\" ") 

On Linux

import os os.system("xdg-open \"\" ") 

Cross-Platform

import webbrowser webbrowser.open(') 

You have to read the data too.

Check out : to understand it.

response = urllib2.urlopen(..) headers = response.info() data = response.read() 

Of course, what you want is to render it in browser and aaronasterling's answer is what you want.

You could also try:

import os os.system("start \"\" ") 

This, other than @aaronasterling ´s answer has the advantage that it opens the default web browser. Be sure not to forget the "http://".

Here is another way to do it.

import webbrowser webbrowser.open("foobar.com") 

I think this is the easy way to open a URL using this function

webbrowser.open_new_tab(url)