How to print a linebreak in a python function?

I have a list of strings in my code;

A = ['a1', 'a2', 'a3' ...] B = ['b1', 'b2', 'b3' ...] 

and I want to print them separated by a linebreak, like this:

>a1 b1 >a2 b2 >a3 b3 

I've tried:

print '>' + A + '/n' + B 

But /n isn't recognized like a line break.

9 Answers

You have your slash backwards, it should be "\n"

The newline character is actually '\n'.

All three way you can use for newline character :

'\n' "\n" """\n""" 

>>> A = ['a1', 'a2', 'a3'] >>> B = ['b1', 'b2', 'b3'] >>> for x in A: for i in B: print ">" + x + "\n" + i 

Outputs:

>a1 b1 >a1 b2 >a1 b3 >a2 b1 >a2 b2 >a2 b3 >a3 b1 >a3 b2 >a3 b3 

Notice that you are using /n which is not correct!

for pair in zip(A, B): print ">"+'\n'.join(pair) 

\n is an escape sequence, denoted by the backslash. A normal forward slash, such as /n will not do the job. In your code you are using /n instead of \n.

You can print a native linebreak using the standard os library

import os with open('test.txt','w') as f: f.write(os.linesep) 

Also if you're making it a console program, you can do: print(" ") and continue your program. I've found it the easiest way to separate my text.

A = ['a1', 'a2', 'a3'] B = ['b1', 'b2', 'b3'] for a,b in zip(A,B): print(f">{a}\n{b}") 

Below python 3.6 instead of print(f">{a}\n{b}") use print(">%s\n%s" % (a, b))