How to use `@ts-ignore` for a block?

The // @ts-ignore comment enables the TypeScript compiler to ignore the line below it.

How can one ignore a whole block of code with TypeScript?

9 Answers

You can't. This is an open issue in TypeScript.

You can't.

As a workaround you can use a // @ts-nocheck comment at the top of a file to disable type-checking for that file:

So to disable checking for a block (function, class, etc.), you can move it into its own file, then use the comment/flag above. (This isn't as flexible as block-based disabling of course, but it's the best option available at the moment.)

There is

// @ts-nocheck 

It can be added at the beginning of the file and all errors in it will be ignored, isn't the block specific answer you are looking for but in some scenarios it is equivalent.

You can use //@ts-nocheck at the top of the file Files

reference: Ignore all errors in a typescript file

you can use // @ts-expect-error to suppress the error on one line, and you can do it for multiple lines ( a bit cumbersome)

BUT WAIT

if you use // @ts-expect-error on line that has no error, it will result in error Unused '@ts-expect-error' directive.

so make sure to only use it on line that has type error

Just use

// @ts-ignore-start typescript is ... // @ts-ignore-end 

If your goal is to ignore some method or property only in the declaration output you can use the internal annotation to do that.

Leaving this here as since this post is the top search result and I came across while searching for a way to ignore things in the declaration output.

If you are using prettier you can add //prettier-ignore for code that is small enough that prettier just turned into more than one line

If you don't need typesafe, just bring block to a new separated file and change the extension to .js,.jsx