Integer.parseInt number format exception?

I feel like I must be missing something simple, but I am getting a NumberFormatException on the following code:

System.out.println(Integer.parseInt("howareyou",35)) 

Ideone

It can convert the String yellow from base 35, I don't understand why I would get a NumberFormatException on this String.

7 Answers

Because the result will get greater than Integer.MAX_VALUE

Try this

System.out.println(Integer.parseInt("yellow", 35)); System.out.println(Long.parseLong("howareyou", 35)); 

and for

Long.parseLong("abcdefghijklmno",25) 

you need BigInteger

Try this and you will see why

System.out.println(Long.MAX_VALUE); System.out.println(new BigInteger("abcdefghijklmno",25)); 

Could it be that the number is > Integer.MAX_VALUE? If I try your code with Long instead, it works.

The number is getting bigger than Integer.MAX_VALUE

Try this:

System.out.println(Integer.parseInt("yellow", 35)); System.out.println(Long.parseLong("howareyou", 35)); 

As seen in René Link comments you are looking for something like this using a BigInteger:

BigInteger big=new BigInteger("abcdefghijklmno", 25); 

Something like this:

System.out.println(Long.MAX_VALUE); System.out.println(new BigInteger("abcdefghijklmno",25)); 

From the JavaDocs:

An exception of type NumberFormatException is thrown if any of the following situations occurs:

• The first argument is null or is a string of length zero. FALSE: "howareyou" is not null and over 0 length
• The radix is either smaller than Character.MIN_RADIX or larger than Character.MAX_RADIX. FALSE: 35 is in range [2,36]
• Any character of the string is not a digit of the specified radix, except that the first character may be a minus sign '-' ('\u002D') or plus sign '+' ('\u002B') provided that the string is longer than length 1. FALSE: all characters of "howareyou" are in radix range [0,'y']
• ==> The value represented by the string is not a value of type int. TRUE: The reason for the exception. The value is too large for an int.

Either Long or BigInteger should be used

As you can see, you're running out of space in your Integer. By swapping it out for a Long, you get the desired result. Here is the IDEOne Link to the working code.

Code

System.out.println(Integer.parseInt("YELLOW",35)); System.out.println(Long.parseLong("HOWAREYOU",35)); 

The previous answers of parseLong would be correct, but sometime that is also not large enough so the other option would to use a BigInteger.

Long.parseLong("howareyou", 35) new BigInteger("howareyou", 35) 

The number produced is too large for a Java Integer, use a Long.