is (i % 3 == 0) means ( i % 3 == false )?

I am a beginner learning JS. Can anyone explain to me why "1" on the output?

here it is:

for (var i = 1; i <= 15; i++) { if (i % 2 == 0) { i += 2; } else if (i % 3 == 0) { i++; } console.log(i); }

output : 1, 4, 5, 8, 10, 11, 14, 16

I can figure out why the output equal to 4, 5, 8, 10, 11, 14, 16 , however, I don't understand why 1 is there as output...

2 Answers

When the value of i is 1, both conditional statement you defined doesn't get executed.

for (var i = 1; i <= 15; i++) { if (i % 2 == 0) { console.log( 'inside if' ); i += 2; } else if (i % 3 == 0) { console.log( 'inside else-if' ); i++; } else { console.log( 'neither if nor else-if' ); } console.log(i); }

Remainder is always 1 when you divide it with 2 or 3, which is not equals to 0.

console.log( 1 % 2 ); console.log( 1 % 3 );

When you look at your code the console is out of if-else condition, means that it is printing i from condition and out of condition, Your for-loop start from 1, when i=1, condition skipped and console executed and print i which is equal to one I think that's why And I % 3 == 0 means I % 3 == false because

var i = 2; if (i % 2 == 0) { console.log(0) } if (i % 2 == false) { console.log(0) } 

all the answer is 0