I'd like to print the value of members and id from below jq output:
$ cat test_|jq -r '.[] | select(.name=="AAA") | .' { "name": "AAA", "members": 10, "profiles": 0, "templates": 0, "ldapGroups": 0, "ldapMembers": 0, "id": "20" } Unfortunately it works for one of each only:
$ cat test_|jq -r '.[] | select(.name=="AAA") | .members' 10 with +" "+ I get error:
$ cat test_|jq -r '.[] | select(.name=="AAA") | .members+" "+.id' jq: error: number and string cannot be added 4 Answers
I recommend to use string interpolation. It will automatically cast input to a string if necessary:
jq -r '.[]|select(.name=="AAA")|"\(.members) \(.id)"' file.json Convert number to string with tostring function:
jq -r '.[] | select(.name=="AAA") | (.members|tostring) +" "+ .id test' You have not specified precisely how you want the two values to appear, so it is worth pointing out that you could write:
.... | (.members, .id) or
.... | [.members, .id] or
.... | [.members, .id] | E where E could be @csv or @tsv or etc. In jq 1.5, join/1 will also do the type conversion.
You could start by just projecting the members of interest. e.g
$ jq -Mc '.[] | select(.name=="AAA") | {members,id}' data.json {"members":10,"id":"20"} Now you can see .members is a number and .id is a string. You can't add them directly with + but you can choose any of the options explained in the other answers.
