NPM clean modules

Is there a way to get npm to unbuild all the modules under node_modules? Something like npm rebuild that removes all build artifacts but doesn't rebuild them?

9 Answers

You can just delete the node_module directory

rm -rf node_modules/ 

There is actually special command for this job

npm ci 

It will delete node_modules directory and will install packages with respect your package-lock.json file

More info:

I added this to my package.json:

"build": "npm build", "clean": "rm -rf node_modules", "reinstall": "npm run clean && npm install", "rebuild": "npm run clean && npm install && npm run build", 

Seems to work well.

Try

npx npkill 

it will find all node_modules and let you remove them.

You can take advantage of the 'npm cache' command which downloads the package tarball and unpacks it into the npm cache directory.

The source can then be copied in.

Using ideas gleaned from I came up with the following node script. No warranties, YMMV, etcetera.

var fs = require('fs'), path = require('path'), exec = require('child_process').exec, util = require('util'); var packageFileName = 'package.json'; var modulesDirName = 'node_modules'; var cacheDirectory = process.cwd(); var npmCacheAddMask = 'npm cache add %s@%s; echo %s'; var sourceDirMask = '%s/%s/%s/package'; var targetDirMask = '%s/node_modules/%s'; function deleteFolder(folder) { if (fs.existsSync(folder)) { var files = fs.readdirSync(folder); files.forEach(function(file) { file = folder + "/" + file; if (fs.lstatSync(file).isDirectory()) { deleteFolder(file); } else { fs.unlinkSync(file); } }); fs.rmdirSync(folder); } } function downloadSource(folder) { var packageFile = path.join(folder, packageFileName); if (fs.existsSync(packageFile)) { var data = fs.readFileSync(packageFile); var package = JSON.parse(data); function getVersion(data) { var version = data.match(/-([^-]+)\.tgz/); return version[1]; } var callback = function(error, stdout, stderr) { var dependency = stdout.trim(); var version = getVersion(stderr); var sourceDir = util.format(sourceDirMask, cacheDirectory, dependency, version); var targetDir = util.format(targetDirMask, folder, dependency); var modulesDir = folder + '/' + modulesDirName; if (!fs.existsSync(modulesDir)) { fs.mkdirSync(modulesDir); } fs.renameSync(sourceDir, targetDir); deleteFolder(cacheDirectory + '/' + dependency); downloadSource(targetDir); }; for (dependency in package.dependencies) { var version = package.dependencies[dependency]; exec(util.format(npmCacheAddMask, dependency, version, dependency), callback); } } } if (!fs.existsSync(path.join(process.cwd(), packageFileName))) { console.log(util.format("Unable to find file '%s'.", packageFileName)); process.exit(); } deleteFolder(path.join(process.cwd(), modulesDirName)); process.env.npm_config_cache = cacheDirectory; downloadSource(process.cwd()); 

In a word no.

In two, not yet.

There is, however, an open issue for a --no-build flag to npm install to perform an installation without building, which could be used to do what you're asking.

See this open issue.

For windows environment:

"scripts": { "clean": "rmdir /s /q node_modules", ... } 

I have added few lines inside package.json:

"scripts": { ... "clean": "rmdir /s /q node_modules", "reinstall": "npm run clean && npm install", "rebuild": "npm run clean && npm install && rmdir /s /q dist && npm run build --prod", ... } 

If you want to clean only you can use this rimraf node_modules.

npm ci works for this scenario, but only when your package.json and package-lock.json are in sync, which might not always be the case if you have been working on either one to resolve conflicts quickly or are updating on the directory level by removing directories/symbolic links. A comprehensive answer to the question would be this..

1. Edit the package.json with what ever you want and remove what you dont need.
2. Generate the package-lock.json like this, npm install --package-lock-only
3. Run npm ci. This should remove all artifacts and shouldn't rebuild them.