Obtaining zeros in this derivative in Jax

Implementing a jacobian for a polar to cartesian coordinates, I obtain an array of zeros in Jax, which it can't be

theta = r = 4.0 var = np.array([r, theta]) x = var[0]*jnp.cos(var[1]) y = var[0]*jnp.sin(var[1]) def f(var): return np.array([x, y]) jac = jax.jacobian(f)(var) jac #DeviceArray([[0., 0.], # [0., 0.]], dtype=float32) 

What am I missing?

1 Answer

Your function has no dependence on var because x, y are defined outside the function.

This would give the desired output instead:

theta = r = 4.0 var = np.array([r, theta]) def f(var): x = var[0]*jnp.cos(var[1]) y = var[0]*jnp.sin(var[1]) return jnp.array([x, y]) jac = jax.jacobian(f)(var) jac 

Note that you need to return a jax numpy array rather than a numpy array as well.

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