pop a specific element off a vector in c++

so suppose I have a vector called v and it has three elements: 1,2,3

is there a way to specifically pop 2 from the vector so the resulting vector becomes

1,3

4 Answers

//erase the i-th element myvector.erase (myvector.begin() + i); 

(Counting the first element in the vector as as i=0)

Assuming you're looking for the element containing the value 2, not the value at index 2.

#include<vector> #include<algorithm> int main(){ std::vector<int> a={1,2,3}; a.erase(std::find(a.begin(),a.end(),2)); } 

(I used C++0x to avoid some boilerplate, but the actual use of std::find and vector::erase doesn't require C++0x)

Also, remember to use the erase-remove idiom if you are removing multiple elements.

#include <iostream> #include <vector> using namespace std; int main () { unsigned int i; vector<unsigned int> myvector; // set some values (from 1 to 10) for (i=1; i<=10; i++) myvector.push_back(i); // erase the 6th element myvector.erase (myvector.begin()+5); // erase the first 3 elements: myvector.erase (myvector.begin(),myvector.begin()+3); cout << "myvector contains:"; for (i=0; i<myvector.size(); i++) cout << " " << myvector[i]; cout << endl; return 0; }