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How to convert a time to a string
I have a variable as shown in the below code.
a = "2011-06-09" Using python, how to convert it to the following format?
"Jun 09,2011" 2 Answers
>>> import datetime >>> d = datetime.datetime.strptime('2011-06-09', '%Y-%m-%d') >>> d.strftime('%b %d,%Y') 'Jun 09,2011' In pre-2.5 Python, you can replace datetime.strptime with time.strptime, like so (untested): datetime.datetime(*(time.strptime('2011-06-09', '%Y-%m-%d')[0:6]))
@Tim's answer only does half the work -- that gets it into a datetime.datetime object.
To get it into the string format you require, you use datetime.strftime:
print(datetime.strftime('%b %d,%Y')) 
