I have a simple entity with one to many relationship
@Entity // and other @ stuff public class Member { @Id private Long id; private String name; private List<Program> programs; ... } @Entity public class Program { @Id private Long id; private Long programName; private ProgramType programType; private Long programCost; ... } Now using QueryDSL, I would like to query 'All members enrolled in a program with programType = "FULLTIME" and programCost > $1000'
I used the following predicate
Predicate predicate = QMember.member.programs.any() .programType.eq(ProgramType.FULLTIME) .and(QMember.member.programs.any().programCost.gt(1000)); with JPARepository
memberRepository.findAll(predicate); Now the problem is that the two queries are independent. It returns al members with at least one program of type 'FULLTIME' or at least one program of cost greater than 1000.
Desired result : Return members if he has at least one program that is of type FULLTIME and cost > 1000.
2 Answers
Basically the conditions on the program need to be in a separate subQuery (a JPASubquery instance)
QProgram program = QProgram.program JPASubQuery subQuery = new JPASubQuery(); subQuery.from(program) .where(program.programType.eq(ProgramType.FULLTIME), program.programCost.gt(1000)); Predicate predicate = QMember.member.name.eq("John") .and(subQuery.exists()); memberRepository.findAll(predicate); 3As mentionned by @Shahbour, this is not working anymore with QueryDsl 4.x+.
I had a similar case (except that my entities are bidirectionnal), and I've solved it with this :
QProgram program = QProgram.program; QProgram member = QProgram.member; Predicate predicate = JPAExpressions .selectOne() .from(program) .where(program.member.id.eq(member.id), program.programCost.gt(1000), program.programType.eq(ProgramType.FULLTIME)) ) .exists(); memberRepository.findAll(predicate); 1