I have some sample string. How can I replace first occurrence of this string in a longer string with empty string?
regex = re.compile('text') match = regex.match(url) if match: url = url.replace(regex, '') 2 Answers
string replace() function perfectly solves this problem:
string.replace(s, old, new[, maxreplace])
Return a copy of string s with all occurrences of substring old replaced by new. If the optional argument maxreplace is given, the first maxreplace occurrences are replaced.
>>> u'longlongTESTstringTEST'.replace('TEST', '?', 1) u'longlong?stringTEST' Use re.sub directly, this allows you to specify a count:
regex.sub('', url, 1) (Note that the order of arguments is replacement, original not the opposite, as might be suspected.)
