I need a code that would run through the possible combinations of 4 numbers e.g 1234 would produce 24 combinations of 1234, 1243, 1324 ... ect ect. But does not do ['1', '12', '123', ect] I want it to be only 4 number length combinations, (just changing the order)
A long option would be to
import random randomise one of the 4 numbers, randomise another and another and another, check if that combination had been printed or like added to an array that held the possible combinations and then eventually printed out all of them.
array = ['1234', '1243', '1342', '1324' ect]
That would take long though and is highly inefficient. Pretty new to coding :) Thanks
2 Answers
The solution using itertools.permutations() and str.join() functions:
import itertools n = '1234' a = [''.join(i) for i in itertools.permutations(n, 4)] print(a) # prints 24 permutations The output:
['1234', '1243', '1324', '1342', '1423', '1432', '2134', '2143', '2314', '2341', '2413', '2431', '3124', '3142', '3214', '3241', '3412', '3421', '4123', '4132', '4213', '4231', '4312', '4321'] You can use the builtin module itertools in python. Refer to this question already asked here
import itertools array = itertools.permutations([1, 2, 3, 4]) for eachpermutation in array: print(eachpermutation ) Should give you the output such as this
(1, 2, 3, 4) (1, 2, 4, 3) (1, 3, 2, 4) (1, 3, 4, 2) (1, 4, 2, 3) (1, 4, 3, 2) (2, 1, 3, 4) (2, 1, 4, 3) (2, 3, 1, 4) (2, 3, 4, 1) (2, 4, 1, 3) (2, 4, 3, 1) (3, 1, 2, 4) (3, 1, 4, 2) (3, 2, 1, 4) (3, 2, 4, 1) (3, 4, 1, 2) (3, 4, 2, 1) (4, 1, 2, 3) (4, 1, 3, 2) (4, 2, 1, 3) (4, 2, 3, 1) (4, 3, 1, 2) (4, 3, 2, 1) If you need to concatenate the sublists into a single number, you can use the answer provided here
for eachpermutation in array: print(int(''.join(str(i) for i in eachpermutation ))) gives you the following output
1234 1243 1324 1342 1423 1432 2134 2143 2314 2341 2413 2431 3124 3142 3214 3241 3412 3421 4123 4132 4213 4231 4312 4321 Hope that helps
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